What is x^2+(y+2)^2=49 ?

The solution to x^2+(y+2)^2=49 is Circle with (a,b)=(0,-2),r=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+(y+2)^2=49

x^{2} + (y + 2)^{2} = 49

(a, b) = (0, - 2), r = 7

Solution steps

x^{2} + (y + 2)^{2} = 49

Rewrite

x^{2} + (y + 2)^{2} = 49

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 2))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, - 2), r = 7

X^{2} + Y^{2} = 4

(x - 1)^{2} + (y + 2)^{2} = 49

(x - \frac{5}{2})^{2} + (y + 2)^{2} = \frac{225}{4}

x^{2} + y^{2} + 6 x + 6 y + 9 = 0

3 x^{2} + 3 y^{2} - 30 x - 30 y - 9 = 0

What is x^2+(y+2)^2=49 ?
The solution to x^2+(y+2)^2=49 is Circle with (a,b)=(0,-2),r=7