What is (x-5/2)^2+(y+2)^2= 225/4 ?

The solution to (x-5/2)^2+(y+2)^2= 225/4 is Circle with (a,b)=(5/2 ,-2),r= 15/2

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(x-5/2)^2+(y+2)^2= 225/4

(x - \frac{5}{2})^{2} + (y + 2)^{2} = \frac{225}{4}

(a, b) = (\frac{5}{2}, - 2), r = \frac{15}{2}

Solution steps

(x - \frac{5}{2})^{2} + (y + 2)^{2} = \frac{225}{4}

Rewrite

(x - \frac{5}{2})^{2} + (y + 2)^{2} = \frac{225}{4}

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- 2))^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - 2), r = \frac{15}{2}

x^{2} + y^{2} + 6 x + 6 y + 9 = 0

3 x^{2} + 3 y^{2} - 30 x - 30 y - 9 = 0

x^{2} + y^{2} + 8 x - 10 y + 37 = 0

(x - 1)^{2} + (y - 1)^{2} = 9

(x - 2)^{2} + (y - 3)^{2} = 5^{2}

What is (x-5/2)^2+(y+2)^2= 225/4 ?
The solution to (x-5/2)^2+(y+2)^2= 225/4 is Circle with (a,b)=(5/2 ,-2),r= 15/2