What is the domain of f(x)=ln(sqrt(x^2)+x-2) ?

The domain of f(x)=ln(sqrt(x^2)+x-2) is x>1

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domain of f(x)=ln(sqrt(x^2)+x-2)

domain

f (x) = ln (x^{2} + x - 2)

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

f (x) = \frac{x ^{2} + x + 1}{x}

(- x^{2} + 16) (x + 3)

f (x) = \frac{3 x ^{2}}{x ^{2} - 9}

y = \frac{3 x - 1}{2 x + 8}

f (x) = - 5

What is the domain of f(x)=ln(sqrt(x^2)+x-2) ?
The domain of f(x)=ln(sqrt(x^2)+x-2) is x>1