What is the domain of f(x)=(x-3)/(2x^2-3x-20) ?

The domain of f(x)=(x-3)/(2x^2-3x-20) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-3)/(2x^2-3x-20)

domain

f (x) = \frac{x - 3}{2 x ^{2} - 3 x - 20}

x < - \frac{5}{2} or - \frac{5}{2} < x < 4 or x > 4

Interval Notation

(- \infty, - \frac{5}{2}) \cup (- \frac{5}{2}, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - \frac{5}{2}

The function domain

x < - \frac{5}{2} or - \frac{5}{2} < x < 4 or x > 4

8 x - 7 y - 14 = 0

f (x) = 6 x^{4} + 32 x^{3}

(3, - 1), (x, 8)

f (x) = \frac{1}{3 x ^{2} - 2 x - 1}

What is the domain of f(x)=(x-3)/(2x^2-3x-20) ?
The domain of f(x)=(x-3)/(2x^2-3x-20) is x<-5/2 \lor-5/2 <x<4\lor x>4