What is the domain of f(x)= 1/(3x^2-2x-1) ?

The domain of f(x)= 1/(3x^2-2x-1) is x 1

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domain of f(x)= 1/(3x^2-2x-1)

domain

f (x) = \frac{1}{3 x ^{2} - 2 x - 1}

x < - \frac{1}{3} or - \frac{1}{3} < x < 1 or x > 1

Interval Notation

(- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - \frac{1}{3}

The function domain

x < - \frac{1}{3} or - \frac{1}{3} < x < 1 or x > 1

f (x) = x^{4} + 3

- cos (t)

\frac{5 - x}{x ^{2} - 4 x}

\frac{2}{x}

3 x + y - 2 = 0

What is the domain of f(x)= 1/(3x^2-2x-1) ?
The domain of f(x)= 1/(3x^2-2x-1) is x<-1/3 \lor-1/3 <x<1\lor x>1