What is the monotone f(x)=-sqrt(x+3) ?

The monotone f(x)=-sqrt(x+3) is Decreasing:-3<x<infinity

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monotone f(x)=-sqrt(x+3)

monotone intervals

f (x) = - x + 3

Decreasing : - 3 < x < \infty

Solution steps

f^{'} (x) = - \frac{1}{2 x + 3}

Find intervals:

Decreasing

: - 3 < x < \infty

Decreasing : - 3 < x < \infty

5 x - 15 y = 17

f (x) = (8 - 4 x) e^{x}

sin (arccos (x))

(- 8, 5), (17, 8)

f (x) = 2 x^{2} - 7 x + 4

What is the monotone f(x)=-sqrt(x+3) ?
The monotone f(x)=-sqrt(x+3) is Decreasing:-3<x<infinity