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Popular >

extreme f(x)=2x^2-7x+4

Solution

extreme points

f (x) = 2 x^{2} - 7 x + 4

Solution

Minimum (\frac{7}{4}, - \frac{17}{8})

Solution steps

f^{'} (x) = 4 x - 7

Find intervals:

Decreasing

: - \infty < x < \frac{7}{4},

Increasing

: \frac{7}{4} < x < \infty

Plug

x = \frac{7}{4}

into

2 x^{2} - 7 x + 4 : - \frac{17}{8}

Minimum (\frac{7}{4}, - \frac{17}{8})

Popular Examples

inflection f(x)=x^4-6x^3 inflection points

f (x) = x^{4} - 6 x^{3}

periodicity of f(x)=sec(3x)periodicity

f (x) = sec (3 x)

symmetry y=4x^6+x^8 symmetry

y = 4 x^{6} + x^{8}

asymptotes of f(x)=(2-5x)/(2+2x)asymptotes

f (x) = \frac{2 - 5 x}{2 + 2 x}

distance (6,1),(2,-3)distance

(6, 1), (2, - 3)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-7x+4 ?
The extreme f(x)=2x^2-7x+4 is Minimum(7/4 ,-17/8)