What is the inverse of-9/((x-7)^2) ?

The inverse of-9/((x-7)^2) is sqrt(-9/x)+7,-sqrt(-9/x)+7

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inverse of-9/((x-7)^2)

inverse

- \frac{9}{( x - 7 ) ^{2}}

- \frac{9}{x} + 7, - - \frac{9}{x} + 7

Solution steps

y = - \frac{9}{( x - 7 ) ^{2}}

Replace

x

with

y

x = - \frac{9}{( y - 7 ) ^{2}}

Solve for

y, x = - \frac{9}{( y - 7 ) ^{2}}

- \frac{9}{x} + 7, - - \frac{9}{x} + 7

f (x) = - 16 x^{2} + 150 x + 6

f (x) = 10 x^{2} - 6 x + 9

y - 1 = 2 (x - 4)

(10.8) (6.2)

f (x) = \frac{( x ^{2} + x - 12 )}{x}

What is the inverse of-9/((x-7)^2) ?
The inverse of-9/((x-7)^2) is sqrt(-9/x)+7,-sqrt(-9/x)+7