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Popular >

range of f(x)=10x^2-6x+9

Solution

range

f (x) = 10 x^{2} - 6 x + 9

Solution

f (x) \geq \frac{81}{10}

+1

Interval Notation

[\frac{81}{10}, \infty)

Solution steps

Vertex of

10 x^{2} - 6 x + 9 :

Minimum

(\frac{3}{10}, \frac{81}{10})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 10,

Vertex

(x_{v}, y_{v}) = (\frac{3}{10}, \frac{81}{10})

f (x) \geq \frac{81}{10}

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Frequently Asked Questions (FAQ)

What is the range of f(x)=10x^2-6x+9 ?
The range of f(x)=10x^2-6x+9 is f(x)>= 81/10