What is the domain of (2x^3-5)/(x^2+x-6) ?

The domain of (2x^3-5)/(x^2+x-6) is x 2

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domain of (2x^3-5)/(x^2+x-6)

domain

\frac{2 x ^{3} - 5}{x ^{2} + x - 6}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

f (x) = - x^{2} - 4 x + 1

f (x) = \frac{( 2 x - 3 )}{4 x + 5}

x^{2} + 2 x - 15

y = \frac{1}{x} + x

(x - 9)^{2} - 6

What is the domain of (2x^3-5)/(x^2+x-6) ?
The domain of (2x^3-5)/(x^2+x-6) is x<-3\lor-3<x<2\lor x>2