What is the inverse of f(x)=-x^2-4x+1 ?

The inverse of f(x)=-x^2-4x+1 is -2-sqrt(-x+5),-2+sqrt(-x+5)

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inverse of f(x)=-x^2-4x+1

inverse

f (x) = - x^{2} - 4 x + 1

- 2 - - x + 5, - 2 + - x + 5

Solution steps

y = - x^{2} - 4 x + 1

Replace

x

with

y

x = - y^{2} - 4 y + 1

Solve for

y, x = - y^{2} - 4 y + 1

- 2 - - x + 5, - 2 + - x + 5

f (x) = \frac{( 2 x - 3 )}{4 x + 5}

x^{2} + 2 x - 15

y = \frac{1}{x} + x

(x - 9)^{2} - 6

y = 2 x + 10

What is the inverse of f(x)=-x^2-4x+1 ?
The inverse of f(x)=-x^2-4x+1 is -2-sqrt(-x+5),-2+sqrt(-x+5)