What is the extreme f(x)=x^3-75x+10 ?

The extreme f(x)=x^3-75x+10 is Maximum(-5,260),Minimum(5,-240)

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extreme f(x)=x^3-75x+10

extreme points

f (x) = x^{3} - 75 x + 10

Maximum (- 5, 260), Minimum (5, - 240)

Solution steps

f^{'} (x) = 3 x^{2} - 75

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{3} - 75 x + 10 : 260

Maximum (- 5, 260)

Plug

x = 5

into

x^{3} - 75 x + 10 : - 240

Minimum (5, - 240)

Maximum (- 5, 260), Minimum (5, - 240)

f (x) = \frac{9 x - 21}{15 x + 35}

f (x) = - (x - 6) (x + 6) (x + 3)

sec (2 x - 3 π)

f (x) = (x - 3) (2 x + 6) 7 x^{3}

- 2 x^{2} + 5 x - 6

What is the extreme f(x)=x^3-75x+10 ?
The extreme f(x)=x^3-75x+10 is Maximum(-5,260),Minimum(5,-240)