What is the domain of f(x)=sqrt((x-3)(2x+6)7x^3) ?

The domain of f(x)=sqrt((x-3)(2x+6)7x^3) is -3 = 3

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domain of f(x)=sqrt((x-3)(2x+6)7x^3)

domain

f (x) = (x - 3) (2 x + 6) 7 x^{3}

- 3 \leq x \leq 0 or x \geq 3

Interval Notation

[- 3, 0] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 0 or x \geq 3

The function domain

- 3 \leq x \leq 0 or x \geq 3

- 2 x^{2} + 5 x - 6

f (x) = (4 x - 5) + (3 x + 2)

\frac{4 x - 3}{6 - 3 x}

\frac{x + 5}{x - 2}

f (x) = \frac{x ^{2}}{x ^{2} - 9}

What is the domain of f(x)=sqrt((x-3)(2x+6)7x^3) ?
The domain of f(x)=sqrt((x-3)(2x+6)7x^3) is -3<= x<= 0\lor x>= 3