What is the inverse of (x^2-4)/(2x^2) ?

The inverse of (x^2-4)/(2x^2) is sqrt(-4/(2x-1)),-sqrt(-4/(2x-1))

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inverse of (x^2-4)/(2x^2)

inverse

\frac{x ^{2} - 4}{2 x ^{2}}

- \frac{4}{2 x - 1}, - - \frac{4}{2 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{2 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{2 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{2 y ^{2}}

- \frac{4}{2 x - 1}, - - \frac{4}{2 x - 1}

f (x) = \frac{6}{x + 4} - \frac{1}{2 - x}

f (x) = - ln (x + 1)

(0, - 2), (5, 3)

f (x) = x^{2} + 1 - x

f (x) = - 3 cos (x)

What is the inverse of (x^2-4)/(2x^2) ?
The inverse of (x^2-4)/(2x^2) is sqrt(-4/(2x-1)),-sqrt(-4/(2x-1))