What is the inverse of f(x)=sqrt(x^2+1)-x ?

The inverse of f(x)=sqrt(x^2+1)-x is (1-x^2)/(2x)

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inverse of f(x)=sqrt(x^2+1)-x

inverse

f (x) = x^{2} + 1 - x

\frac{1 - x ^{2}}{2 x}

Solution steps

y = x^{2} + 1 - x

Replace

x

with

y

x = y^{2} + 1 - y

Solve for

y, x = y^{2} + 1 - y

\frac{1 - x ^{2}}{2 x}

f (x) = - 3 cos (x)

2 x + y = 7

g (x) = - 3 x

- 0.8 x^{2} + 3.2 x + 6

f (x) = x^{2} - 4 x + 7

What is the inverse of f(x)=sqrt(x^2+1)-x ?
The inverse of f(x)=sqrt(x^2+1)-x is (1-x^2)/(2x)