What is the derivative of f(x)=(2ln(x))/x ?

The derivative of f(x)=(2ln(x))/x is (2(1-ln(x)))/(x^2)

What is the first derivative of f(x)=(2ln(x))/x ?

The first derivative of f(x)=(2ln(x))/x is (2(1-ln(x)))/(x^2)

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derivative of

f (x) = \frac{2 ln ( x )}{x}

\frac{2 ( 1 - ln ( x ) )}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 ln ( x )}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{ln ( x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( ln ( x ) ) x - \frac{d x}{d x} ln ( x )}{x ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= 2 \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( x )}{x ^{2}}

Simplify

2 \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( x )}{x ^{2}} : \frac{2 ( 1 - ln ( x ) )}{x ^{2}}

= \frac{2 ( 1 - ln ( x ) )}{x ^{2}}

\frac{\partial}{\partial x} (2 x (4 + y)^{- 1})

\frac{d}{d x} (- 2 (e^{x} sin (x) + cos (x) e^{x}))

\int \frac{1}{5 + 2 x ^{4}} (8 x^{3}) d x

\frac{d}{d x} (8 sin (x) - 4 2 x)

What is the derivative of f(x)=(2ln(x))/x ?
The derivative of f(x)=(2ln(x))/x is (2(1-ln(x)))/(x^2)
What is the first derivative of f(x)=(2ln(x))/x ?
The first derivative of f(x)=(2ln(x))/x is (2(1-ln(x)))/(x^2)