What is (\partial)/(\partial x)(2x(4+y)^{-1}) ?

The answer to (\partial)/(\partial x)(2x(4+y)^{-1}) is 2/(4+y)

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(\partial)/(\partial x)(2x(4+y)^{-1})

\frac{\partial}{\partial x} (2 x (4 + y)^{- 1})

\frac{2}{4 + y}

Solution steps

\frac{\partial}{\partial x} (2 x (4 + y)^{- 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 (4 + y)^{- 1} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 (4 + y)^{- 1} \cdot 1

Simplify

2 (4 + y)^{- 1} \cdot 1 : \frac{2}{4 + y}

= \frac{2}{4 + y}

\frac{d}{d x} (- 2 (e^{x} sin (x) + cos (x) e^{x}))

\int \frac{1}{5 + 2 x ^{4}} (8 x^{3}) d x

\frac{d}{d x} (8 sin (x) - 4 2 x)

{cos (t)}

What is (\partial)/(\partial x)(2x(4+y)^{-1}) ?
The answer to (\partial)/(\partial x)(2x(4+y)^{-1}) is 2/(4+y)