What is the derivative of sin(cos(4x)) ?

The derivative of sin(cos(4x)) is -4cos(cos(4x))sin(4x)

What is the first derivative of sin(cos(4x)) ?

The first derivative of sin(cos(4x)) is -4cos(cos(4x))sin(4x)

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\frac{d}{d x} (sin (cos (4 x)))

- 4 cos (cos (4 x)) sin (4 x)

Solution steps

\frac{d}{d x} (sin (cos (4 x)))

Apply the chain rule:

cos (cos (4 x)) \frac{d}{d x} (cos (4 x))

= cos (cos (4 x)) \frac{d}{d x} (cos (4 x))

\frac{d}{d x} (cos (4 x)) = - sin (4 x) \cdot 4

= cos (cos (4 x)) (- sin (4 x) \cdot 4)

Simplify

= - 4 cos (cos (4 x)) sin (4 x)

\frac{1}{5 x ^{\frac{4}{5}}}

f (x) = \frac{x ^{3} + 1}{x ^{3} - 1}

x^{3} y^{^{'''}} + x y^{^{'}} - y = 0

\int e^{- 1}

f (x) = \frac{2 ln ( x )}{x}

What is the derivative of sin(cos(4x)) ?
The derivative of sin(cos(4x)) is -4cos(cos(4x))sin(4x)
What is the first derivative of sin(cos(4x)) ?
The first derivative of sin(cos(4x)) is -4cos(cos(4x))sin(4x)