What is the derivative of f(x)=(x^2+4x+3)^2 ?

The derivative of f(x)=(x^2+4x+3)^2 is 2(x^2+4x+3)(2x+4)

What is the first derivative of f(x)=(x^2+4x+3)^2 ?

The first derivative of f(x)=(x^2+4x+3)^2 is 2(x^2+4x+3)(2x+4)

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derivative of

f (x) = (x^{2} + 4 x + 3)^{2}

2 (x^{2} + 4 x + 3) (2 x + 4)

Solution steps

\frac{d}{d x} ((x^{2} + 4 x + 3)^{2})

Apply the chain rule:

2 (x^{2} + 4 x + 3) \frac{d}{d x} (x^{2} + 4 x + 3)

= 2 (x^{2} + 4 x + 3) \frac{d}{d x} (x^{2} + 4 x + 3)

\frac{d}{d x} (x^{2} + 4 x + 3) = 2 x + 4

= 2 (x^{2} + 4 x + 3) (2 x + 4)

n = 1 \sum \infty \frac{n}{2 ^{n - 1}}

y^{^{'}} - \frac{1}{x} y = 1

y = \frac{1}{4 + 3 x}, (1, \frac{1}{7})

f^{^{'}} (x) = 2 - 4

What is the derivative of f(x)=(x^2+4x+3)^2 ?
The derivative of f(x)=(x^2+4x+3)^2 is 2(x^2+4x+3)(2x+4)
What is the first derivative of f(x)=(x^2+4x+3)^2 ?
The first derivative of f(x)=(x^2+4x+3)^2 is 2(x^2+4x+3)(2x+4)