What is the integral of \sqrt[3]{x^6} ?

The integral of \sqrt[3]{x^6} is (x^3)/3+C

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integral of \sqrt[3]{x^6}

\frac{x ^{3}}{3} + C

Solution steps

assuming

x \geq 0

= \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{x ^{3}}{3}

Add a constant to the solution

= \frac{x ^{3}}{3} + C

\frac{d}{d x} (e^{x} sec (x))

\int \frac{sin ^{3} ( x )}{cos ^{3} ( x )} d x

\frac{d}{d x} (8 x^{\frac{1}{2}})

\frac{d}{d x} (15 e^{\frac{1}{x}})

x \to 0 + lim (x ln (tan (9 x)))

What is the integral of \sqrt[3]{x^6} ?
The integral of \sqrt[3]{x^6} is (x^3)/3+C