What is the solution for y^{''}x=-5sin(8x) ?

The solution for y^{''}x=-5sin(8x) is y=integral of-5\Si(8x)+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}x=-5sin(8x)

y^{^{''}} x = - 5 sin (8 x)

y = \int - 5 Si (8 x) + c_{1} d x

Solution steps

y^{''} (x) x = - 5 sin (8 x)

Isolate

y^{''} (x) : y^{''} (x) = - \frac{5 sin ( 8 x )}{x}

Solve

y^{''} (x) = - \frac{5 sin ( 8 x )}{x} : y^{'} (x) = - 5 Si (8 x) + c_{1}

Solve

y^{'} (x) = - 5 Si (8 x) + c_{1} : y = \int - 5 Si (8 x) + c_{1} d x

y = \int - 5 Si (8 x) + c_{1} d x

\frac{\partial}{\partial x} (x ln (z^{7} + x^{5}))

f (x) = (x^{2} + 4 x + 3)^{2}

n = 1 \sum \infty \frac{n}{2 ^{n - 1}}

y^{^{'}} - \frac{1}{x} y = 1

y = \frac{1}{4 + 3 x}, (1, \frac{1}{7})

What is the solution for y^{''}x=-5sin(8x) ?
The solution for y^{''}x=-5sin(8x) is y=integral of-5\Si(8x)+c_{1}