What is the integral of 1/(u^{1/2)} ?

The integral of 1/(u^{1/2)} is 2u^{1/2}+C

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integral of 1/(u^{1/2)}

\int \frac{1}{u ^{\frac{1}{2}}} d u

2 u^{\frac{1}{2}} + C

Solution steps

\int \frac{1}{u ^{\frac{1}{2}}} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 2 u^{\frac{1}{2}}

Add a constant to the solution

= 2 u^{\frac{1}{2}} + C

n = 0 \sum \infty \frac{n}{3 ^{n + 1}}

\frac{\partial}{\partial x} (\frac{- y - x y}{( 1 + x ) ^{3}})

\int \frac{1}{x ^{2} + 25} d x

\int x (1 + x)^{4} d x

y^{^{'}} = t - y t