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Popular >

y^'=t-yt

Solution

y^{^{'}} = t - y t

Solution

y = e^{- \frac{t ^{2}}{2} + c_{1}} + 1

Solution steps

y^{'} (t) = t - y t

Solve separable ODE:

y = e^{- \frac{t ^{2}}{2} + c_{1}} + 1

y = e^{- \frac{t ^{2}}{2} + c_{1}} + 1

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\int \frac{18}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=t-yt ?
The solution for y^'=t-yt is y=e^{-(t^2)/2+c_{1}}+1