What is the derivative of (4x^3+1^2) ?

The derivative of (4x^3+1^2) is 24x^2(4x^3+1)

What is the first derivative of (4x^3+1^2) ?

The first derivative of (4x^3+1^2) is 24x^2(4x^3+1)

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\frac{d}{d x} ((4 x^{3} + 1)^{2})

24 x^{2} (4 x^{3} + 1)

Solution steps

\frac{d}{d x} ((4 x^{3} + 1)^{2})

Apply the chain rule:

2 (4 x^{3} + 1) \frac{d}{d x} (4 x^{3} + 1)

= 2 (4 x^{3} + 1) \frac{d}{d x} (4 x^{3} + 1)

\frac{d}{d x} (4 x^{3} + 1) = 12 x^{2}

= 2 (4 x^{3} + 1) \cdot 12 x^{2}

Simplify

= 24 x^{2} (4 x^{3} + 1)

\int sin^{2} (X) d X

\frac{d}{d x} (6 cos (π x))

x \to + 0 lim (\frac{sin ( 4 x )}{tan ( 2 x )})

f (x) = a x + b

\frac{d}{d x} ((4 x^{2} + 3)^{2})

What is the derivative of (4x^3+1^2) ?
The derivative of (4x^3+1^2) is 24x^2(4x^3+1)
What is the first derivative of (4x^3+1^2) ?
The first derivative of (4x^3+1^2) is 24x^2(4x^3+1)