What is the derivative of f(x)=ax+b ?

The derivative of f(x)=ax+b is a

What is the first derivative of f(x)=ax+b ?

The first derivative of f(x)=ax+b is a

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derivative of

f (x) = a x + b

a

Solution steps

\frac{d}{d x} (a x + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x) + \frac{d b}{d x}

\frac{d}{d x} (a x) = a

\frac{d b}{d x} = 0

= a + 0

Simplify

= a

\frac{d}{d x} ((4 x^{2} + 3)^{2})

y = x (x^{4} + 1)

\int_{0}^{1} arcsin (w) d w

x \to 0 + lim (x^{x})

\frac{d}{d x} (arcsin (1 - x^{2}))

What is the derivative of f(x)=ax+b ?
The derivative of f(x)=ax+b is a
What is the first derivative of f(x)=ax+b ?
The first derivative of f(x)=ax+b is a