What is the tangent of f(x)=(36x)/(x^2+36),(-3,-12/5) ?

The tangent of f(x)=(36x)/(x^2+36),(-3,-12/5) is y= 12/25 x-24/25

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tangent of f(x)=(36x)/(x^2+36),(-3,-12/5)

tangent of

f (x) = \frac{36 x}{x ^{2} + 36}, (- 3, - \frac{12}{5})

y = \frac{12}{25} x - \frac{24}{25}

Solution steps

Find the slope of

f (x) = \frac{36 x}{x ^{2} + 36} : \frac{df ( x )}{d x} = \frac{36 ( - x ^{2} + 36 )}{( x ^{2} + 36 ) ^{2}}

Compute the slope of

f (x) = \frac{36 x}{x ^{2} + 36}

(- 3, - \frac{12}{5}) : m = \frac{12}{25}

Find the line with slope m=

\frac{12}{25}

and passing through

(- 3, - \frac{12}{5}) : y = \frac{12}{25} x - \frac{24}{25}

y = \frac{12}{25} x - \frac{24}{25}

\frac{d}{d x} ((sin (x) + cos (x)) sec (x) d x)

\frac{d}{d x} (\frac{6 x}{x ^{2} + 2})

\int t^{2} - cos (2 π) t d t

\int sin^{2} (d) t

\frac{d}{d x} ((16 x)^{3})

What is the tangent of f(x)=(36x)/(x^2+36),(-3,-12/5) ?
The tangent of f(x)=(36x)/(x^2+36),(-3,-12/5) is y= 12/25 x-24/25