What is the integral of t^2-cos(2pi)t ?

The integral of t^2-cos(2pi)t is (t^3)/3-(t^2)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of t^2-cos(2pi)t

\int t^{2} - cos (2 π) t d t

\frac{t ^{3}}{3} - \frac{t ^{2}}{2} + C

Solution steps

\int t^{2} - cos (2 π) t d t

cos (2 π) t = t

= \int t^{2} - t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int t^{2} d t - \int t d t

\int t^{2} d t = \frac{t ^{3}}{3}

\int t d t = \frac{t ^{2}}{2}

= \frac{t ^{3}}{3} - \frac{t ^{2}}{2}

Add a constant to the solution

= \frac{t ^{3}}{3} - \frac{t ^{2}}{2} + C

\int sin^{2} (d) t

\frac{d}{d x} ((16 x)^{3})

f (x) = - 2 sin (2 x)

\int x^{4} - 2 x^{2} + 1 d x

\int (8 x - 9) d x

What is the integral of t^2-cos(2pi)t ?
The integral of t^2-cos(2pi)t is (t^3)/3-(t^2)/2+C