What is the derivative of f(x)=4x+1 ?

The derivative of f(x)=4x+1 is 4

What is the first derivative of f(x)=4x+1 ?

The first derivative of f(x)=4x+1 is 4

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derivative of

f (x) = 4 x + 1

4

Solution steps

\frac{d}{d x} (4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 4 + 0

Simplify

= 4

x \to 0 - lim (x^{2} (sin (\frac{1}{x})))

\frac{d}{d x} (\frac{2 x + 1}{x + 5})

\int (\frac{7}{x} - \frac{6}{x ^{3}}) d x

(x, y) \to (1, - 1) lim ((e^{- x y}) (cos (x + y)))

\int + 2 x^{2} sec^{2} (x^{3} + 1) d x

What is the derivative of f(x)=4x+1 ?
The derivative of f(x)=4x+1 is 4
What is the first derivative of f(x)=4x+1 ?
The first derivative of f(x)=4x+1 is 4