What is the limit as x approaches 0-of x^2(sin(1/x)) ?

The limit as x approaches 0-of x^2(sin(1/x)) is 0

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limit as x approaches 0-of x^2(sin(1/x))

x \to 0 - lim (x^{2} (sin (\frac{1}{x})))

0

Solution steps

x \to 0 - lim (x^{2} sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

\frac{d}{d x} (\frac{2 x + 1}{x + 5})

\int (\frac{7}{x} - \frac{6}{x ^{3}}) d x

(x, y) \to (1, - 1) lim ((e^{- x y}) (cos (x + y)))

\int + 2 x^{2} sec^{2} (x^{3} + 1) d x

\int x 1 + 2 x d x

What is the limit as x approaches 0-of x^2(sin(1/x)) ?
The limit as x approaches 0-of x^2(sin(1/x)) is 0