What is the integral of e^xsqrt(9+e^x) ?

The integral of e^xsqrt(9+e^x) is 2/3 (9+e^x)^{3/2}+C

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integral of e^xsqrt(9+e^x)

\int e^{x} 9 + e^{x} d x

\frac{2}{3} (9 + e^{x})^{\frac{3}{2}} + C

Solution steps

\int e^{x} 9 + e^{x} d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 9 + e^{x}

= \frac{2}{3} (9 + e^{x})^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (9 + e^{x})^{\frac{3}{2}} + C

\frac{d}{d x} (2^{x^{2} c o t (3 x)})

\frac{d}{d x} (x sin (e^{x}))

\frac{d y}{d x} + 2 y = 3, y (0) = 1

f (x) = x^{4} + 8 x

\frac{d}{d x} (\frac{g ( x )}{h ( x )})

What is the integral of e^xsqrt(9+e^x) ?
The integral of e^xsqrt(9+e^x) is 2/3 (9+e^x)^{3/2}+C