What is the derivative of f(x)=x^4+8x ?

The derivative of f(x)=x^4+8x is 4x^3+8

What is the first derivative of f(x)=x^4+8x ?

The first derivative of f(x)=x^4+8x is 4x^3+8

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derivative of

f (x) = x^{4} + 8 x

4 x^{3} + 8

Solution steps

\frac{d}{d x} (x^{4} + 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (8 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x) = 8

= 4 x^{3} + 8

\frac{d}{d x} (\frac{g ( x )}{h ( x )})

f (x) = 4 x - 8

\int 9 x cos (3 x) d x

\int e^{- x} \cdot cos (2 x) d x

\frac{d}{d x} (- sin (x))

What is the derivative of f(x)=x^4+8x ?
The derivative of f(x)=x^4+8x is 4x^3+8
What is the first derivative of f(x)=x^4+8x ?
The first derivative of f(x)=x^4+8x is 4x^3+8