What is the derivative of (4x+7^2) ?

The derivative of (4x+7^2) is 8(4x+7)

What is the first derivative of (4x+7^2) ?

The first derivative of (4x+7^2) is 8(4x+7)

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\frac{d}{d x} ((4 x + 7)^{2})

8 (4 x + 7)

Solution steps

\frac{d}{d x} ((4 x + 7)^{2})

Apply the chain rule:

2 (4 x + 7) \frac{d}{d x} (4 x + 7)

= 2 (4 x + 7) \frac{d}{d x} (4 x + 7)

\frac{d}{d x} (4 x + 7) = 4

= 2 (4 x + 7) \cdot 4

Simplify

= 8 (4 x + 7)

x \to 4 lim ((1 + \frac{x}{3})^{2})

\int 3 u^{5} - 2 u^{3} d u

v^{2}

\frac{d}{d x} (\frac{4 e ^{4 x}}{e ^{8} ( e ^{16} - 1 )})

y = sin (x), at x = \frac{5 π}{3}

What is the derivative of (4x+7^2) ?
The derivative of (4x+7^2) is 8(4x+7)
What is the first derivative of (4x+7^2) ?
The first derivative of (4x+7^2) is 8(4x+7)