What is the tangent of y=sin(x),\at x=(5pi)/3 ?

The tangent of y=sin(x),\at x=(5pi)/3 is y= 1/2 x-(sqrt(3))/2-(5pi)/6

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tangent of y=sin(x),\at x=(5pi)/3

tangent of

y = sin (x), at x = \frac{5 π}{3}

y = \frac{1}{2} x - \frac{3}{2} - \frac{5 π}{6}

Solution steps

Find the tangent point:

(\frac{5 π}{3}, - \frac{3}{2})

Find the slope of

y = sin (x) : \frac{d y}{d x} = cos (x)

Compute the slope of

y = sin (x)

x = \frac{5 π}{3} : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(\frac{5 π}{3}, - \frac{3}{2}) : y = \frac{1}{2} x - \frac{3}{2} - \frac{5 π}{6}

y = \frac{1}{2} x - \frac{3}{2} - \frac{5 π}{6}

x \to 0 lim (\frac{5 ^{x} - 7 ^{x}}{x})

x \to 0 lim (\frac{x ^{2} - 3}{x})

\frac{d y}{d x} (2) - 4 x y = 8 x

\int 8^{3 x + 1} d x

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 25})

What is the tangent of y=sin(x),\at x=(5pi)/3 ?
The tangent of y=sin(x),\at x=(5pi)/3 is y= 1/2 x-(sqrt(3))/2-(5pi)/6