What is the integral of 6^{(x-2)} ?

The integral of 6^{(x-2)} is (6^{x-2})/(ln(6))+C

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integral of 6^{(x-2)}

\int 6^{(x - 2)} d x

\frac{6 ^{x - 2}}{ln ( 6 )} + C

Solution steps

\int 6^{x - 2} d x

Apply u-substitution

: \int 6^{u} d u

= \int 6^{u} d u

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{6 ^{u}}{ln ( 6 )}

Substitute back

u = x - 2

= \frac{6 ^{x - 2}}{ln ( 6 )}

Add a constant to the solution

= \frac{6 ^{x - 2}}{ln ( 6 )} + C

\int \frac{1}{5 - x ^{2} - 4 x} d x

x^{3} \frac{d y}{d x} = y^{2} + 1

\int \frac{12}{( x ^{2} - 6 x + 13 ) ^{2}} d x

\int (x^{2} - 9)^{3} (2 x) d x

y = 8 x, (16, 32)

What is the integral of 6^{(x-2)} ?
The integral of 6^{(x-2)} is (6^{x-2})/(ln(6))+C