What is the solution for x^3(dy)/(dx)=y^2+1 ?

The solution for x^3(dy)/(dx)=y^2+1 is y=tan(-1/(2x^2)+c_{1})

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x^3(dy)/(dx)=y^2+1

x^{3} \frac{d y}{d x} = y^{2} + 1

y = tan (- \frac{1}{2 x ^{2}} + c_{1})

Solution steps

x^{3} \frac{d y}{d x} = y^{2} + 1

Solve separable ODE:

y = tan (- \frac{1}{2 x ^{2}} + c_{1})

y = tan (- \frac{1}{2 x ^{2}} + c_{1})

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What is the solution for x^3(dy)/(dx)=y^2+1 ?
The solution for x^3(dy)/(dx)=y^2+1 is y=tan(-1/(2x^2)+c_{1})