What are the solutions to the equation 3x^2+8x+4=0 ?

The solutions to the equation 3x^2+8x+4=0 are x=-2/3 ,x=-2

Find the zeros of 3x^2+8x+4=0

The zeros of 3x^2+8x+4=0 are x=-2/3 ,x=-2

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3 x^{2} + 8 x + 4 = 0

x = - \frac{2}{3}, x = - 2

Decimal Notation

x = - 0.66666 \dots, x = - 2

Solution steps

3 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 4 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 3}, x_{2} = \frac{- 8 - 4}{2 \cdot 3}

x = \frac{- 8 + 4}{2 \cdot 3} : - \frac{2}{3}

x = \frac{- 8 - 4}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 2

2 x^{2} - 16 x = - 30

\frac{\frac{1}{12}}{\frac{1}{6}}

2 x^{2} - 12 x + 11 = 0

n^{2} + 18 n + 5200 = 0

(5 x + 3)^{2} = 16

What are the solutions to the equation 3x^2+8x+4=0 ?
The solutions to the equation 3x^2+8x+4=0 are x=-2/3 ,x=-2
Find the zeros of 3x^2+8x+4=0
The zeros of 3x^2+8x+4=0 are x=-2/3 ,x=-2