What are the solutions to the equation (5x+3)^2=16 ?

The solutions to the equation (5x+3)^2=16 are x= 1/5 ,x=-7/5

Find the zeros of (5x+3)^2=16

The zeros of (5x+3)^2=16 are x= 1/5 ,x=-7/5

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(5 x + 3)^{2} = 16

x = \frac{1}{5}, x = - \frac{7}{5}

Decimal Notation

x = 0.2, x = - 1.4

Solution steps

(5 x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 3 = 16 : x = \frac{1}{5}

Solve

5 x + 3 = - 16 : x = - \frac{7}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{7}{5}

- 1 < 2 x - 1 \leq 7

\frac{5}{6} - \frac{7}{12}

x^{2} - 64 < 0

\frac{12}{3 + 3}

(3 + \frac{1}{4}) (1 - \frac{4}{5})

What are the solutions to the equation (5x+3)^2=16 ?
The solutions to the equation (5x+3)^2=16 are x= 1/5 ,x=-7/5
Find the zeros of (5x+3)^2=16
The zeros of (5x+3)^2=16 are x= 1/5 ,x=-7/5