What are the solutions to the equation y^2+3y-6=0 ?

The solutions to the equation y^2+3y-6=0 are y=(-3+sqrt(33))/2 ,y=(-3-sqrt(33))/2

Find the zeros of y^2+3y-6=0

The zeros of y^2+3y-6=0 are y=(-3+sqrt(33))/2 ,y=(-3-sqrt(33))/2

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y^{2} + 3 y - 6 = 0

y = \frac{- 3 + 33}{2}, y = \frac{- 3 - 33}{2}

Decimal Notation

y = 1.37228 \dots, y = - 4.37228 \dots

Solution steps

y^{2} + 3 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 6) = 33

y_{1, 2} = \frac{- 3 \pm 33}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 3 + 33}{2 \cdot 1}, y_{2} = \frac{- 3 - 33}{2 \cdot 1}

y = \frac{- 3 + 33}{2 \cdot 1} : \frac{- 3 + 33}{2}

y = \frac{- 3 - 33}{2 \cdot 1} : \frac{- 3 - 33}{2}

The solutions to the quadratic equation are:

y = \frac{- 3 + 33}{2}, y = \frac{- 3 - 33}{2}

3 x^{2} + 8 x + 4 = 0

2 x^{2} - 16 x = - 30

\frac{\frac{1}{12}}{\frac{1}{6}}

2 x^{2} - 12 x + 11 = 0

n^{2} + 18 n + 5200 = 0

What are the solutions to the equation y^2+3y-6=0 ?
The solutions to the equation y^2+3y-6=0 are y=(-3+sqrt(33))/2 ,y=(-3-sqrt(33))/2
Find the zeros of y^2+3y-6=0
The zeros of y^2+3y-6=0 are y=(-3+sqrt(33))/2 ,y=(-3-sqrt(33))/2