What is factor m^8-n^8 ?

The solution to factor m^8-n^8 is (m^4+n^4)(m^2+n^2)(m+n)(m-n)

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factor m^8-n^8

factor

m^{8} - n^{8}

(m^{4} + n^{4}) (m^{2} + n^{2}) (m + n) (m - n)

Solution steps

m^{8} - n^{8}

m^{8} = (m^{4})^{2}

n^{8} = (n^{4})^{2}

= (m^{4})^{2} - (n^{4})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(m^{4})^{2} - (n^{4})^{2} = (m^{4} + n^{4}) (m^{4} - n^{4})

= (m^{4} + n^{4}) (m^{4} - n^{4})

Factor

m^{4} - n^{4} : (m^{2} + n^{2}) (m + n) (m - n)

= (m^{4} + n^{4}) (m^{2} + n^{2}) (m + n) (m - n)

(8 \frac{2}{3})^{4}

- 12 \leq 2 x

- 6 y^{3} + 18 y^{4}

\frac{1}{10} \times \frac{9}{9} + \frac{9}{10} \times \frac{1}{9}

0 = - 5 t^{2} + 15 t

What is factor m^8-n^8 ?
The solution to factor m^8-n^8 is (m^4+n^4)(m^2+n^2)(m+n)(m-n)