What are the solutions to the equation 0=-5t^2+15t ?

The solutions to the equation 0=-5t^2+15t are t=0,t=3

Find the zeros of 0=-5t^2+15t

The zeros of 0=-5t^2+15t are t=0,t=3

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0 = - 5 t^{2} + 15 t

t = 0, t = 3

Solution steps

0 = - 5 t^{2} + 15 t

Switch sides

- 5 t^{2} + 15 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

1 5^{2} - 4 (- 5) \cdot 0 = 15

t_{1, 2} = \frac{- 15 \pm 15}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 15 + 15}{2 ( - 5 )}, t_{2} = \frac{- 15 - 15}{2 ( - 5 )}

t = \frac{- 15 + 15}{2 ( - 5 )} : 0

t = \frac{- 15 - 15}{2 ( - 5 )} : 3

The solutions to the quadratic equation are:

t = 0, t = 3

t^{2} + \frac{3}{2} t - \frac{2}{3} = 0

76 \cdot 1 0^{- 12} s^{2} + 30 \cdot 1 0^{- 4} s + 820 = 0

ab + 2 a + 3 b + 6

\frac{1}{4} x^{2} - 1 = 15

\frac{n - 5}{2} = 5

What are the solutions to the equation 0=-5t^2+15t ?
The solutions to the equation 0=-5t^2+15t are t=0,t=3
Find the zeros of 0=-5t^2+15t
The zeros of 0=-5t^2+15t are t=0,t=3