What are the solutions to the equation 3n^2+n-80=0 ?

The solutions to the equation 3n^2+n-80=0 are n=5,n=-16/3

Find the zeros of 3n^2+n-80=0

The zeros of 3n^2+n-80=0 are n=5,n=-16/3

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3 n^{2} + n - 80 = 0

n = 5, n = - \frac{16}{3}

Decimal Notation

n = 5, n = - 5.33333 \dots

Solution steps

3 n^{2} + n - 80 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 80 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 80) = 31

n_{1, 2} = \frac{- 1 \pm 31}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 1 + 31}{2 \cdot 3}, n_{2} = \frac{- 1 - 31}{2 \cdot 3}

n = \frac{- 1 + 31}{2 \cdot 3} : 5

n = \frac{- 1 - 31}{2 \cdot 3} : - \frac{16}{3}

The solutions to the quadratic equation are:

n = 5, n = - \frac{16}{3}

5 (x + 1) = 4 x + 7

\frac{4}{15} - \frac{4}{5} + \frac{1}{2}

3 x^{2} - 23 x y + 40 y^{2}

\frac{104 p ^{11}}{18 q ^{4}}

4 x^{2} + 7 x = 10

What are the solutions to the equation 3n^2+n-80=0 ?
The solutions to the equation 3n^2+n-80=0 are n=5,n=-16/3
Find the zeros of 3n^2+n-80=0
The zeros of 3n^2+n-80=0 are n=5,n=-16/3