What are the solutions to the equation 4x^2+7x=10 ?

The solutions to the equation 4x^2+7x=10 are x=(-7+sqrt(209))/8 ,x=(-7-sqrt(209))/8

Find the zeros of 4x^2+7x=10

The zeros of 4x^2+7x=10 are x=(-7+sqrt(209))/8 ,x=(-7-sqrt(209))/8

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4 x^{2} + 7 x = 10

x = \frac{- 7 + 209}{8}, x = \frac{- 7 - 209}{8}

Decimal Notation

x = 0.93210 \dots, x = - 2.68210 \dots

Solution steps

4 x^{2} + 7 x = 10

Move

10

to the left side

4 x^{2} + 7 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 10) = 209

x_{1, 2} = \frac{- 7 \pm 209}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 209}{2 \cdot 4}, x_{2} = \frac{- 7 - 209}{2 \cdot 4}

x = \frac{- 7 + 209}{2 \cdot 4} : \frac{- 7 + 209}{8}

x = \frac{- 7 - 209}{2 \cdot 4} : \frac{- 7 - 209}{8}

The solutions to the quadratic equation are:

x = \frac{- 7 + 209}{8}, x = \frac{- 7 - 209}{8}

2 x^{2} + 5 x - 52

5 x + 50 x^{2} + 80

4192

(2 x - 1) (x + 1) < 0

\frac{2}{\frac{3}{2}}

What are the solutions to the equation 4x^2+7x=10 ?
The solutions to the equation 4x^2+7x=10 are x=(-7+sqrt(209))/8 ,x=(-7-sqrt(209))/8
Find the zeros of 4x^2+7x=10
The zeros of 4x^2+7x=10 are x=(-7+sqrt(209))/8 ,x=(-7-sqrt(209))/8