What are the solutions to the equation (1-2x)^2-8=0 ?

The solutions to the equation (1-2x)^2-8=0 are x=-(2sqrt(2)-1)/2 ,x=(2sqrt(2)+1)/2

Find the zeros of (1-2x)^2-8=0

The zeros of (1-2x)^2-8=0 are x=-(2sqrt(2)-1)/2 ,x=(2sqrt(2)+1)/2

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(1 - 2 x)^{2} - 8 = 0

x = - \frac{2 2 - 1}{2}, x = \frac{2 2 + 1}{2}

Decimal Notation

x = - 0.91421 \dots, x = 1.91421 \dots

Solution steps

(1 - 2 x)^{2} - 8 = 0

Move

8

to the right side

(1 - 2 x)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - 2 x = 8 : x = - \frac{2 2 - 1}{2}

Solve

1 - 2 x = - 8 : x = \frac{2 2 + 1}{2}

The solutions to the quadratic equation are:

x = - \frac{2 2 - 1}{2}, x = \frac{2 2 + 1}{2}

x^{2} - 8 x = 9 x

\frac{2 x}{5} = \frac{x + 4}{3}

1 + 2 x + x^{2} = 0

5 x^{2} + 50 x = - 125

X - 12 = 14

What are the solutions to the equation (1-2x)^2-8=0 ?
The solutions to the equation (1-2x)^2-8=0 are x=-(2sqrt(2)-1)/2 ,x=(2sqrt(2)+1)/2
Find the zeros of (1-2x)^2-8=0
The zeros of (1-2x)^2-8=0 are x=-(2sqrt(2)-1)/2 ,x=(2sqrt(2)+1)/2