What are the solutions to the equation 1+2x+x^2=0 ?

The solutions to the equation 1+2x+x^2=0 are x=-1

Find the zeros of 1+2x+x^2=0

The zeros of 1+2x+x^2=0 are x=-1

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1 + 2 x + x^{2} = 0

x = - 1

Solution steps

1 + 2 x + x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

5 x^{2} + 50 x = - 125

X - 12 = 14

1 + \frac{0.25}{100}

x^{2} - 7 x + 12 = 0

- \frac{3}{4} + 1

What are the solutions to the equation 1+2x+x^2=0 ?
The solutions to the equation 1+2x+x^2=0 are x=-1
Find the zeros of 1+2x+x^2=0
The zeros of 1+2x+x^2=0 are x=-1