What are the solutions to the equation 4x^2-29x-63=0 ?

The solutions to the equation 4x^2-29x-63=0 are x=9,x=-7/4

Find the zeros of 4x^2-29x-63=0

The zeros of 4x^2-29x-63=0 are x=9,x=-7/4

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4 x^{2} - 29 x - 63 = 0

x = 9, x = - \frac{7}{4}

Decimal Notation

x = 9, x = - 1.75

Solution steps

4 x^{2} - 29 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 4 ( - 63 )}{2 \cdot 4}

(- 29)^{2} - 4 \cdot 4 (- 63) = 43

x_{1, 2} = \frac{- ( - 29 ) \pm 43}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 43}{2 \cdot 4}, x_{2} = \frac{- ( - 29 ) - 43}{2 \cdot 4}

x = \frac{- ( - 29 ) + 43}{2 \cdot 4} : 9

x = \frac{- ( - 29 ) - 43}{2 \cdot 4} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 9, x = - \frac{7}{4}

95 = - 4 + 33 x

(x - 4)^{2} = 64

1 \leq ∣ 3 - 2 x ∣ < 5

\frac{1}{8} + \frac{1}{8}

f (g (1))

What are the solutions to the equation 4x^2-29x-63=0 ?
The solutions to the equation 4x^2-29x-63=0 are x=9,x=-7/4
Find the zeros of 4x^2-29x-63=0
The zeros of 4x^2-29x-63=0 are x=9,x=-7/4