What are the solutions to the equation (x-4)^2=64 ?

The solutions to the equation (x-4)^2=64 are x=12,x=-4

Find the zeros of (x-4)^2=64

The zeros of (x-4)^2=64 are x=12,x=-4

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(x - 4)^{2} = 64

x = 12, x = - 4

Solution steps

(x - 4)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 64 : x = 12

Solve

x - 4 = - 64 : x = - 4

The solutions to the quadratic equation are:

x = 12, x = - 4

1 \leq ∣ 3 - 2 x ∣ < 5

\frac{1}{8} + \frac{1}{8}

f (g (1))

(11 - 2 x) (5 - 2 x) \geq 0

2 x - 5 > - 11 or - 10 x - 6 \geq 44

What are the solutions to the equation (x-4)^2=64 ?
The solutions to the equation (x-4)^2=64 are x=12,x=-4
Find the zeros of (x-4)^2=64
The zeros of (x-4)^2=64 are x=12,x=-4