What are the solutions to the equation 4x^2-x-3=-3 ?

The solutions to the equation 4x^2-x-3=-3 are x= 1/4 ,x=0

Find the zeros of 4x^2-x-3=-3

The zeros of 4x^2-x-3=-3 are x= 1/4 ,x=0

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4 x^{2} - x - 3 = - 3

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

4 x^{2} - x - 3 = - 3

Move

3

to the left side

4 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 4}

x = \frac{- ( - 1 ) + 1}{2 \cdot 4} : \frac{1}{4}

x = \frac{- ( - 1 ) - 1}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

x (x - 3) \leq 28

- 2 x^{2} + 8 x - 3 = 0

\frac{a}{4} - \frac{a + 2}{3} = 9

\frac{7 π}{6} + 2 π (1)

4 x^{2} - 16 > 0

What are the solutions to the equation 4x^2-x-3=-3 ?
The solutions to the equation 4x^2-x-3=-3 are x= 1/4 ,x=0
Find the zeros of 4x^2-x-3=-3
The zeros of 4x^2-x-3=-3 are x= 1/4 ,x=0