What are the solutions to the equation -2x^2+8x-3=0 ?

The solutions to the equation -2x^2+8x-3=0 are x=(4-sqrt(10))/2 ,x=(4+sqrt(10))/2

Find the zeros of -2x^2+8x-3=0

The zeros of -2x^2+8x-3=0 are x=(4-sqrt(10))/2 ,x=(4+sqrt(10))/2

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- 2 x^{2} + 8 x - 3 = 0

x = \frac{4 - 10}{2}, x = \frac{4 + 10}{2}

Decimal Notation

x = 0.41886 \dots, x = 3.58113 \dots

Solution steps

- 2 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 3) = 210

x_{1, 2} = \frac{- 8 \pm 2 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 10}{2 ( - 2 )}, x_{2} = \frac{- 8 - 2 10}{2 ( - 2 )}

x = \frac{- 8 + 2 10}{2 ( - 2 )} : \frac{4 - 10}{2}

x = \frac{- 8 - 2 10}{2 ( - 2 )} : \frac{4 + 10}{2}

The solutions to the quadratic equation are:

x = \frac{4 - 10}{2}, x = \frac{4 + 10}{2}

\frac{a}{4} - \frac{a + 2}{3} = 9

\frac{7 π}{6} + 2 π (1)

4 x^{2} - 16 > 0

4 - b < - 2

∣ 5 x + 9 ∣ = 4 x

What are the solutions to the equation -2x^2+8x-3=0 ?
The solutions to the equation -2x^2+8x-3=0 are x=(4-sqrt(10))/2 ,x=(4+sqrt(10))/2
Find the zeros of -2x^2+8x-3=0
The zeros of -2x^2+8x-3=0 are x=(4-sqrt(10))/2 ,x=(4+sqrt(10))/2