What are the solutions to the equation 98=0.5*v^2-(2.551*32.2) ?

The solutions to the equation 98=0.5*v^2-(2.551*32.2) are v=(87sqrt(119))/(50),v=-(87sqrt(119))/(50)

Find the zeros of 98=0.5*v^2-(2.551*32.2)

The zeros of 98=0.5*v^2-(2.551*32.2) are v=(87sqrt(119))/(50),v=-(87sqrt(119))/(50)

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98 = 0.5 \cdot v^{2} - (2.551 \cdot 32.2)

v = \frac{87 119}{50}, v = - \frac{87 119}{50}

Decimal Notation

v = 18.98115 \dots, v = - 18.98115 \dots

Solution steps

98 = 0.5 v^{2} - (2.551 \cdot 32.2)

Expand

0.5 v^{2} - (2.551 \cdot 32.2) : 0.5 v^{2} - 82.1422

98 = 0.5 v^{2} - 82.1422

Switch sides

0.5 v^{2} - 82.1422 = 98

Move

82.1422

to the right side

0.5 v^{2} = 180.1422

Divide both sides by

0.5

v^{2} = \frac{180.1422}{0.5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = \frac{180.1422}{0.5}, v = - \frac{180.1422}{0.5}

\frac{180.1422}{0.5} = \frac{87 119}{50}

- \frac{180.1422}{0.5} = - \frac{87 119}{50}

v = \frac{87 119}{50}, v = - \frac{87 119}{50}

\frac{- 9}{3}

12 x^{2} - x - 6 = 0

5 y + 16 = 3 y + 6 y - 12

9 x^{2} + x - 9 = 0

(x + 4)^{2} = - 49

What are the solutions to the equation 98=0.5*v^2-(2.551*32.2) ?
The solutions to the equation 98=0.5*v^2-(2.551*32.2) are v=(87sqrt(119))/(50),v=-(87sqrt(119))/(50)
Find the zeros of 98=0.5*v^2-(2.551*32.2)
The zeros of 98=0.5*v^2-(2.551*32.2) are v=(87sqrt(119))/(50),v=-(87sqrt(119))/(50)