What are the solutions to the equation 9x^2+x-9=0 ?

The solutions to the equation 9x^2+x-9=0 are x=(-1+5sqrt(13))/(18),x=(-1-5sqrt(13))/(18)

Find the zeros of 9x^2+x-9=0

The zeros of 9x^2+x-9=0 are x=(-1+5sqrt(13))/(18),x=(-1-5sqrt(13))/(18)

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9 x^{2} + x - 9 = 0

x = \frac{- 1 + 5 13}{18}, x = \frac{- 1 - 5 13}{18}

Decimal Notation

x = 0.94598 \dots, x = - 1.05709 \dots

Solution steps

9 x^{2} + x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 9 ( - 9 )}{2 \cdot 9}

1^{2} - 4 \cdot 9 (- 9) = 513

x_{1, 2} = \frac{- 1 \pm 5 13}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 1 + 5 13}{2 \cdot 9}, x_{2} = \frac{- 1 - 5 13}{2 \cdot 9}

x = \frac{- 1 + 5 13}{2 \cdot 9} : \frac{- 1 + 5 13}{18}

x = \frac{- 1 - 5 13}{2 \cdot 9} : \frac{- 1 - 5 13}{18}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5 13}{18}, x = \frac{- 1 - 5 13}{18}

(x + 4)^{2} = - 49

- 1 \leq 2 x - 3 < 5

2 x + 10

10 x - 2 x y + 35 - 7 y

8 z^{2} - 7 z - 3 = 0

What are the solutions to the equation 9x^2+x-9=0 ?
The solutions to the equation 9x^2+x-9=0 are x=(-1+5sqrt(13))/(18),x=(-1-5sqrt(13))/(18)
Find the zeros of 9x^2+x-9=0
The zeros of 9x^2+x-9=0 are x=(-1+5sqrt(13))/(18),x=(-1-5sqrt(13))/(18)